Load its inductance is calculated as follows: Coil formula Impedance (ohm) = 2 * 3.14159 * F (operating frequency) * Inductance (mH), set the required 360ohm impedance, thus: Inductance (mH) = impedance (ohm) ÷ (2 * 3.14159) ÷ F (operating frequency) = 360 ÷ (2 * 3.14159) ÷ 7.06 = 8.116mH Accordingly wound coils can be calculated: Number of turns = [inductance * {(18 * circle diameter (inches)) + (40 * Cycle Length (inches))}] ÷ circle diameter (inches) Number of turns = [8.116 * {(18 * 2.047) + (40 * 3.74)}] ÷ 2.047 = 19 laps Core inductor formula Core inductor formula: L (mH) = (0.08DDNN) / (3D + 9W + 10H) Coil diameter D ------ N ------ turns d ----- Wire H ---- coils height W ---- coils width In mm and mH. . Hollow coil inductance calculation formula: l = (0.01 * D * N * N) / (L / D + 0.44) Coil inductance l Unit: microhenry Coil diameter D unit: cm The number of turns N units: Turn The coil length L Unit: cm Frequency inductor-capacitor formula: l = 25330.3 / [(f0 * f0) * c] Operating frequency: f0 unit: MHZ this question f0 = 125KHZ = 0.125 Resonant capacitor: c unit: PF This question Jianyi c = 500 ... 1000pf may first decide on their own, or by the Q Value determination Resonant inductor: l Unit: microhenry Inductance of the coil is calculated Author: posted inductance of the coil is calculated from: Reproduced Hits: 299 1. For ring CORE, the following formula can be used: (IRON)
L = N2. AL L = inductance (H) H-DC = 0.4πNI / l N = number of turns (turns) AL = inductance H-DC = DC magnetizing force through the current I = (A) l = magnetic path length (cm) l AL value and size, can refer Micrometal table. For example: In T50-52 material, coil 5 laps and a half, its L value T50-52 (represented OD of 0.5 inches), the look-up table its AL value of approximately 33nH L = 33. (5.5) 2 = 998.25nH ≒ 1μH When electric current flows through 10A, the L value changes by l = 3.74 (look-up table) H-DC = 0.4πNI / l = 0.4 × 3.14 × 5.5 × 10 / 3.74 = 18.47 (after a look-up table) L value decreased to understand the extent of (μi%) 2. Introduce an empirical formula L = (k * μ0 * μs * N2 * S) / l among them μ0 is the vacuum permeability = 4π * 10 (-7). (10 minus seven square) relative permeability μs is inside the coil core, μs = 1 when the air-core coil N2 is the number of turns squared Cross-sectional area S of the coil, the unit is square meters l coil length in meters k factor, depending on the coil radius (R) and length (l) ratio. Calculate the inductance Henrys. k value table 2R / l k 0.1 0.96 0.2 0.92 0.3 0.88 0.4 0.85 0.6 0.79 0.8 0.74 1.0 0.69 1.5 0.6 2.0 0.52 3.0 0.43 4.0 0.37 5.0 0.32 10 0.2 20 0.12 |